I installed recently AsteriskNow beta6, that is a rpath based Linux distribution, which contains Asterisk 1.4.9 and AsteriskGUI.
While I was trying to use with a SNOM phone (which, by the way, is a great product) with two identies configured on it, say 101 and 103, I stumbled on a problem well known on the web.
If I try to use an identity calling out, everything is working fine; while if I try to use the other identity, I obtain the following error:
WARNING[32233]: chan_sip.c:8126 check_auth: username mismatch, have <101>, digest has <103>
The users 101 and 103 are created with the GUI. If you look in /etc/asterisk/users.conf you will find something like this:
[101]
callwaiting = yes
cid_number =
context = numberplan-custom-1
fullname = 101
hasagent = no
hasdirectory = no
hasiax = no
hasmanager = no
hassip = yes
hasvoicemail = yes
host = dynamic
mailbox = 101
secret = xxx
threewaycalling = yes
vmsecret = xxx
registersip = yes
canreinvite = yes
nat = no
dtmfmode = rfc2833
disallow = all
allow = ulaw,alaw
[103]
callwaiting = yesWorkaround
cid_number =
context = numberplan-custom-1
fullname = 103
hasagent = no
hasdirectory = no
hasiax = no
hasmanager = no
hassip = yes
hasvoicemail = yes
host = dynamic
mailbox = 103
secret = xxx
threewaycalling = yes
vmsecret = xxx
registersip = yes
canreinvite = yes
nat = no
dtmfmode = rfc2833
disallow = all
allow = ulaw,alaw
Workaround
I solved the problem, at least in my installation, using a workaround. I just copied and adapted the above definitions in the file /etc/asterik/sip.conf. This file is not touched by the GUI, so you can edit it safely. Just remember to modify it if you modify the users definition with the GUI, in order to reflect the variations of users.conf. The relevant part of sip.conf looks like:
[101]
type = friend;
context = numberplan-custom-1;
secret = xxx
host = dynamic ;
dtmfmode = rfc2833;
disallow = all
allow = ulaw,alaw;
canreinvite = yes
[103]
type = friend;
context = numberplan-custom-1;
secret = xxx
host = dynamic ;
dtmfmode = rfc2833;
disallow = all
allow = ulaw,alaw;
canreinvite = yes
Well, it seems to work.

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